Version string comparison in Java
1. Use maven API - DefaultArtifactVersion class
import org.apache.maven.artifact.versioning.DefaultArtifactVersion; DefaultArtifactVersion minVersion = new DefaultArtifactVersion("1.0.1"); DefaultArtifactVersion maxVersion = new DefaultArtifactVersion("1.10"); DefaultArtifactVersion version = new DefaultArtifactVersion("1.11"); if (version.compareTo(minVersion) == -1 || version.compareTo(maxVersion) == 1) { System.out.println("Sorry, your version is unsupported"); }
2. Create a VersionComparator class
// VersionComprator.java import java.util.Comparator; public VersionComprator implements Comparator { public boolean equals(Object o1, Object o2) { return compare(o1, o2) == 0; } public int compare(Object o1, Object o2) { String version1 = (String) o1; String version2 = (String) o2; VersionTokenizer tokenizer1 = new VersionTokenizer(version1); VersionTokenizer tokenizer2 = new VersionTokenizer(version2); int number1 = 0, number2 = 0; String suffix1 = "", suffix2 = ""; while (tokenizer1.MoveNext()) { if (!tokenizer2.MoveNext()) { do { number1 = tokenizer1.getNumber(); suffix1 = tokenizer1.getSuffix(); if (number1 != 0 || suffix1.length() != 0) { // Version one is longer than number two, and non-zero return 1; } } while (tokenizer1.MoveNext()); // Version one is longer than version two, but zero return 0; } number1 = tokenizer1.getNumber(); suffix1 = tokenizer1.getSuffix(); number2 = tokenizer2.getNumber(); suffix2 = tokenizer2.getSuffix(); if (number1 < number2) { // Number one is less than number two return -1; } if (number1 > number2) { // Number one is greater than number two return 1; } boolean empty1 = suffix1.length() == 0; boolean empty2 = suffix2.length() == 0; if (empty1 && empty2) continue; // No suffixes if (empty1) return 1; // First suffix is empty (1.2 > 1.2b) if (empty2) return -1; // Second suffix is empty (1.2a < 1.2) // Lexical comparison of suffixes int result = suffix1.compareTo(suffix2); if (result != 0) return result; } if (tokenizer2.MoveNext()) { do { number2 = tokenizer2.getNumber(); suffix2 = tokenizer2.getSuffix(); if (number2 != 0 || suffix2.length() != 0) { // Version one is longer than version two, and non-zero return -1; } } while (tokenizer2.MoveNext()); // Version two is longer than version one, but zero return 0; } return 0; } } // VersionTokenizer.java public class VersionTokenizer { private final String _versionString; private final int _length; private int _position; private int _number; private String _suffix; private boolean _hasValue; public int getNumber() { return _number; } public String getSuffix() { return _suffix; } public VersionTokenizer(String versionString) { if (versionString == null) throw new IllegalArgumentException("versionString is null"); _versionString = versionString; _length = versionString.length(); } public boolean MoveNext() { _number = 0; _suffix = ""; _hasValue = false; // No more characters if (_position >= _length) return false; _hasValue = true; while (_position < _length) { char c = _versionString.charAt(_position); if (c < '0' || c > '9') break; _number = _number * 10 + (c - '0'); _position++; } int suffixStart = _position; while (_position < _length) { char c = _versionString.charAt(_position); if (c == '.') break; _position++; } _suffix = _versionString.substring(suffixStart, _position); if (_position < _length) _position++; return true; } }
Reference: http://stackoverflow.com/questions/198431/how-do-you-compare-two-version-strings-in-java
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